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RomanToInteger13.java
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/**
* Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M.
*
* Symbol Value
* I 1
* V 5
* X 10
* L 50
* C 100
* D 500
* M 1000
* For example, two is written as II in Roman numeral, just two one's added
* together. Twelve is written as, XII, which is simply X + II. The number
* twenty seven is written as XXVII, which is XX + V + II.
*
* Roman numerals are usually written largest to smallest from left to right.
* However, the numeral for four is not IIII. Instead, the number four is
* written as IV. Because the one is before the five we subtract it making four.
* The same principle applies to the number nine, which is written as IX. There
* are six instances where subtraction is used:
*
* I can be placed before V (5) and X (10) to make 4 and 9.
* X can be placed before L (50) and C (100) to make 40 and 90.
* C can be placed before D (500) and M (1000) to make 400 and 900.
* Given a roman numeral, convert it to an integer. Input is guaranteed to be
* within the range from 1 to 3999.
*
* Example 1:
* Input: "III"
* Output: 3
*
* Example 2:
* Input: "IV"
* Output: 4
*
* Example 3:
* Input: "IX"
* Output: 9
*
* Example 4:
* Input: "LVIII"
* Output: 58
* Explanation: C = 100, L = 50, XXX = 30 and III = 3.
*
* Example 5:
* Input: "MCMXCIV"
* Output: 1994
* Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.
*/
public class RomanToInteger13 {
public int romanToInt(String s) {
int res = 0;
int i = 0;
while (i < s.length()) {
char c = s.charAt(i);
switch (c) {
case 'I':
if (i+1 < s.length()) {
char next = s.charAt(i+1);
if (next == 'V') {
res += 4;
i += 2;
} else if (next == 'X') {
res += 9;
i += 2;
} else {
res += 1;
i++;
}
} else {
res += 1;
i++;
}
break;
case 'V':
res += 5;
i++;
break;
case 'X':
if (i+1 < s.length()) {
char next = s.charAt(i+1);
if (next == 'L') {
res += 40;
i += 2;
} else if (next == 'C') {
res += 90;
i += 2;
} else {
res += 10;
i++;
}
} else {
res += 10;
i++;
}
break;
case 'L':
res += 50;
i++;
break;
case 'C':
if (i+1 < s.length()) {
char next = s.charAt(i+1);
if (next == 'D') {
res += 400;
i += 2;
} else if (next == 'M') {
res += 900;
i += 2;
} else {
res += 100;
i++;
}
} else {
res += 100;
i++;
}
break;
case 'D':
res += 500;
i++;
break;
case 'M':
res += 1000;
i++;
break;
default:
return 0;
}
}
return res;
}
/**
* https://leetcode.com/problems/roman-to-integer/discuss/6509/7ms-solution-in-Java.-easy-to-understand
*/
public int romanToInt2(String s) {
int nums[]=new int[s.length()];
for(int i=0;i<s.length();i++){
switch (s.charAt(i)){
case 'M':
nums[i]=1000;
break;
case 'D':
nums[i]=500;
break;
case 'C':
nums[i]=100;
break;
case 'L':
nums[i]=50;
break;
case 'X' :
nums[i]=10;
break;
case 'V':
nums[i]=5;
break;
case 'I':
nums[i]=1;
break;
}
}
int sum=0;
for(int i=0;i<nums.length-1;i++){
if(nums[i]<nums[i+1])
sum-=nums[i];
else
sum+=nums[i];
}
return sum+nums[nums.length-1];
}
}