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Copy pathflip-equivalent-binary-trees.py
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flip-equivalent-binary-trees.py
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from typing import Optional
# Definition for a binary tree node.
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def flipEquiv(self, root1: TreeNode, root2: TreeNode) -> bool:
def compare(
node_left_left: Optional[TreeNode],
node_left_right: Optional[TreeNode],
node_right_left: Optional[TreeNode],
node_right_right: Optional[TreeNode],
) -> bool:
node_left_left_val = node_left_left.val if node_left_left else -1
node_left_right_val = node_left_right.val if node_left_right else -1
node_right_left_val = node_right_left.val if node_right_left else -1
node_right_right_val = node_right_right.val if node_right_right else -1
return (node_left_left_val, node_left_right_val) == (
node_right_left_val,
node_right_right_val,
)
def dfs(left: Optional[TreeNode], right: Optional[TreeNode]) -> bool:
if not left and not right:
return True
if not (left and right) or left.val != right.val:
return False
if compare(left.left, left.right, right.left, right.right):
return dfs(left.left, right.left) and dfs(right.right, left.right)
elif compare(left.right, left.left, right.left, right.right):
return dfs(left.left, right.right) and dfs(left.right, right.left)
else:
return False
return dfs(root1, root2)