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I found out that when an invariant statement outputs false it is immediately executed again before throwing the InvariantViolationException. Is this correct?
Kind regards,
Thijs
The text was updated successfully, but these errors were encountered:
Thanks for the reply!
It is not affecting my application's behavior too much, but I noticed it in my debug-logging and I do not see the logic: each executing gives the same result so why is there more than one validation phase?
Hi Flavio,
I found out that when an invariant statement outputs false it is immediately executed again before throwing the InvariantViolationException. Is this correct?
Kind regards,
Thijs
The text was updated successfully, but these errors were encountered: