-
Notifications
You must be signed in to change notification settings - Fork 819
/
ValidPalindrome.java
40 lines (38 loc) · 1.15 KB
/
ValidPalindrome.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
package string;
/**
* Created by gouthamvidyapradhan on 13/07/2017. Given a string, determine if it is a palindrome,
* considering only alphanumeric characters and ignoring cases.
*
* <p>For example, "A man, a plan, a canal: Panama" is a palindrome. "race a car" is not a
* palindrome.
*
* <p>Note: Have you consider that the string might be empty? This is a good question to ask during
* an interview.
*
* <p>For the purpose of this problem, we define empty string as valid palindrome.
*/
public class ValidPalindrome {
public static void main(String[] args) throws Exception {
System.out.println(new ValidPalindrome().isPalindrome("989 "));
}
public boolean isPalindrome(String s) {
if (s == null || s.isEmpty()) return true;
s = s.toLowerCase();
for (int i = 0, j = s.length() - 1; i < j; ) {
char f = s.charAt(i);
char l = s.charAt(j);
if (!(f >= 'a' && f <= 'z') && !(f >= '0' && f <= '9')) {
i++;
continue;
}
if (!(l >= 'a' && l <= 'z') && !(l >= '0' && l <= '9')) {
j--;
continue;
}
if (f != l) return false;
i++;
j--;
}
return true;
}
}