fix: gracefully exit on interrupt

Catch KeyboardInterrupt and asyncio.CancelledError exceptions to ensure
the application exits without printing traceback on interrupt. This
allows gptscript to kill the provider silently.

Signed-off-by: Nick Hale <4175918+njhale@users.noreply.github.com>

Author: njhale

main.py

@@ -357,6 +357,10 @@ def map_finish_reason(finish_reason: str) -> str:
 
 if __name__ == "__main__":
     import uvicorn
+    import asyncio
 
-    uvicorn.run("main:app", host="127.0.0.1", port=int(os.environ.get("PORT", "8000")),
+    try:
+        uvicorn.run("main:app", host="127.0.0.1", port=int(os.environ.get("PORT", "8000")),
                 log_level="debug" if debug else "critical", reload=debug, access_log=debug)
+    except (KeyboardInterrupt, asyncio.CancelledError):
+        pass