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doubleinsert
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doubleinsert
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Source: "https://www.hackerrank.com/challenges/insert-a-node-into-a-sorted-doubly-linked-list/problem"
Problem Statement
Given a reference to the head of a doubly-linked list and
an integer, data, create a new DoublyLinkedListNode object
having data value data and insert it into a sorted linked
list while maintaining the sort.
Code:
#function
def sortedInsert(head, data):
nnode = DoublyLinkedListNode(data)
if head == None:
return nnode
elif data<head.data:
nnode.next = head
head.prev = nnode
return nnode
else:
nnode = sortedInsert(head.next, data)
head.next = nnode
nnode.prev = head
return head
#Complete Code
#!/bin/python3
import math
import os
import random
import re
import sys
class DoublyLinkedListNode:
def __init__(self, node_data):
self.data = node_data
self.next = None
self.prev = None
class DoublyLinkedList:
def __init__(self):
self.head = None
self.tail = None
def insert_node(self, node_data):
node = DoublyLinkedListNode(node_data)
if not self.head:
self.head = node
else:
self.tail.next = node
node.prev = self.tail
self.tail = node
def print_doubly_linked_list(node, sep, fptr):
while node:
fptr.write(str(node.data))
node = node.next
if node:
fptr.write(sep)
# Complete the sortedInsert function below.
#
# For your reference:
#
# DoublyLinkedListNode:
# int data
# DoublyLinkedListNode next
# DoublyLinkedListNode prev
#
#
def sortedInsert(head, data):
nnode = DoublyLinkedListNode(data)
if head == None:
return nnode
elif data<head.data:
nnode.next = head
head.prev = nnode
return nnode
else:
nnode = sortedInsert(head.next, data)
head.next = nnode
nnode.prev = head
return head
if __name__ == '__main__':
fptr = open(os.environ['OUTPUT_PATH'], 'w')
t = int(input())
for t_itr in range(t):
llist_count = int(input())
llist = DoublyLinkedList()
for _ in range(llist_count):
llist_item = int(input())
llist.insert_node(llist_item)
data = int(input())
llist1 = sortedInsert(llist.head, data)
print_doubly_linked_list(llist1, ' ', fptr)
fptr.write('\n')
fptr.close()