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对于未知的map或者list,也能编译 #16

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javamonkey opened this issue Jun 3, 2013 · 0 comments
Open

对于未知的map或者list,也能编译 #16

javamonkey opened this issue Jun 3, 2013 · 0 comments
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@javamonkey
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for(x in xxx) ,因为如果判断不了xxx类型,则解释执行,遇到这种情况,可以wrapper一下,然后再warpper里解释执行,获取元素

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