How to validate: when on array is length n

[royipressburger]

Hi

I have the next object:

{
   arrayA: [1,2,3],
   arrayB: [
     { a: 1, b: 2, c:3 },
   ],
}

I would like to validate that:

1. On arrayB: a and b are required if arrayA includes 1.
2. On arrayB: c is required if arrayB length is bigger then 1.

array().when('arrayA', { // this is working!
   is: arrayA => arrayA.includes(1),
   then: array().of(object().shape({a: string().required(), b: string().required() })),
}).when('arrayB', { // this is not working! How do I get the value of arrayB here?
   is: arrayB => arrayB.length > 1,
   then: array().of(object().shape({ c: string().required() })),
});

[royipressburger]

K just found out that I was running an old version 0.26 and version 0.27 has self reference.

pull request here;

so the solution:

array().when('arrayA', { // this is working!
   is: arrayA => arrayA.includes(1),
   then: array().of(object().shape({a: string().required(), b: string().required() })),
}).when({ // just pass the object as first argument and is function will get arrayB
   is: arrayB => arrayB.length > 1,
   then: array().of(object().shape({ c: string().required() })),
});