Update consecutive-available-seats-ii.sql

Author: kamyu104

MySQL/consecutive-available-seats-ii.sql

@@ -8,18 +8,18 @@ WITH window_cte AS (
     FROM Cinema
     WHERE free = 1
 ), group_cte AS (
-    SELECT seat_id, (rnk + seat_id) AS group_number
+    SELECT seat_id, (rnk + seat_id) AS group_id
     FROM window_cte
-), order_cte AS (
+), segment_cte AS (
     SELECT MIN(seat_id) AS first_seat_id,
            MAX(seat_id) AS last_seat_id,
            COUNT(*) AS consecutive_seats_len
     FROM group_cte
-    GROUP BY group_number
+    GROUP BY group_id
     ORDER BY NULL
 )
 
 SELECT *
-FROM order_cte
-WHERE consecutive_seats_len = (SELECT MAX(consecutive_seats_len) FROM order_cte)
+FROM segment_cte
+WHERE consecutive_seats_len = (SELECT MAX(consecutive_seats_len) FROM segment_cte)
 ORDER BY 1;