-
Notifications
You must be signed in to change notification settings - Fork 0
/
challange-496.js
35 lines (33 loc) · 1.63 KB
/
challange-496.js
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
// problem
// The next greater element of some element x in an array is the first greater element that is to the right of x in the same array.
// You are given two distinct 0-indexed integer arrays nums1 and nums2, where nums1 is a subset of nums2.
// For each 0 <= i < nums1.length, find the index j such that nums1[i] == nums2[j] and determine the next greater element of nums2[j] in nums2. If there is no next greater element, then the answer for this query is -1.
// Return an array ans of length nums1.length such that ans[i] is the next greater element as described above.
// Example 1:
// Input: nums1 = [4,1,2], nums2 = [1,3,4,2]
// Output: [-1,3,-1]
// Explanation: The next greater element for each value of nums1 is as follows:
// - 4 is underlined in nums2 = [1,3,4,2]. There is no next greater element, so the answer is -1.
// - 1 is underlined in nums2 = [1,3,4,2]. The next greater element is 3.
// - 2 is underlined in nums2 = [1,3,4,2]. There is no next greater element, so the answer is -1.
// solution
var nextGreaterElement = function(nums1, nums2) {
let ans = []
for(let i=0; i< nums1.length; i++){
let counter = 1
const iNum1OnNum2 = nums2.indexOf(nums1[i])
if(nums2[iNum1OnNum2+1] > nums2[iNum1OnNum2]){
ans.push(nums2[iNum1OnNum2+1])
} else if(iNum1OnNum2 < nums2.length-2) {
while(nums2[iNum1OnNum2+1+counter] <nums2[iNum1OnNum2]){
counter ++
}
if(nums2[iNum1OnNum2+1+counter]){
ans.push(nums2[iNum1OnNum2+1+counter])
} else ans.push(-1)
} else {
ans.push(-1)
}
}
return ans
};