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对于任意一个节点,先遍历他的左子树,再遍历右子树,再遍历本身。
function Node(val) { this.left = null; this.right = null; this.value = val; } function generateBST(root,array) { var length = array.length; for (var i = 1; i < length; i ++) { insertNode(root, array[i]); } } function insertNode(node, value) { if (value < node.value) { if (node.left === null) { node.left = new Node(value); } else { node = node.left; insertNode(node, value); } } else { if (node.right === null) { node.right = new Node(value); } else { node = node.right; insertNode(node, value); } } } var array = [2, 3, 4, 12, 3, 54, 6, 7, 1]; var root = new Node(array[0]); generateBST(root, array); // 后序遍历 function postOrderSearch(root) { var array = []; _postOrderSearch(root, array); return array; } function _postOrderSearch(node, array) { if (!node) { return; } _postOrderSearch(node.left, array); _postOrderSearch(node.right, array); array.push(node.value); } console.log(postOrderSearch(root));
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二叉树的后序遍历
对于任意一个节点,先遍历他的左子树,再遍历右子树,再遍历本身。
实现
The text was updated successfully, but these errors were encountered: