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The following example results in a error
const chain = (fn) => (state) => (...args) => { const result = R.apply(fn << state, args); ...
Where as when using pipe forward in the same situation works fine.
const chain = (fn) => (state) => (...args) => { const result = R.apply(fn >> state, args); ...
I suspect this is due if (t.isCallExpression(path.parent)) { being too simple of a check when chaining the pipe backward operator.
if (t.isCallExpression(path.parent)) {
The text was updated successfully, but these errors were encountered:
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The following example results in a error
Where as when using pipe forward in the same situation works fine.
I suspect this is due
if (t.isCallExpression(path.parent)) {
being too simple of a check when chaining the pipe backward operator.The text was updated successfully, but these errors were encountered: