Cannot resolve starting jupyter if active interpreter doesn't support jupyter

[rchiodo]

I have an active interpreter that doesn't support jupyter.

I open a notebook and pick an interpreter that does have jupyter.

I try to run (with ZMQ disabled).

I get this:

In the picture you can see that I have 'condaEnvTest' selected but then it's saying the 'EmptyVenv' doesn't have jupyter installed. Why is it using 'EmptyVenv', well because it's the active interpreter.

This is because the code here:

vscode-jupyter/src/kernels/jupyter/launcher/jupyterExecution.ts

Line 85 in efc80e4

public async getUsableJupyterPython(cancelToken?: CancellationToken): Promise<PythonEnvironment | undefined> {

Doesn't allow passing of any kernel information. It should be able to use the currently selected interpreter.

[greazer]

Pulling from iteration-candidate and milestone, due to Ian's review yesterday.

[DonJayamanne]

Doesn't allow passing of any kernel information. It should be able to use the currently selected interpreter.

i think this should,

• check interpreter in currently select led kernel
• then check selected interpret as well

this way if tomorrow python extension changes their code to properly select the interpreter that's active in their terminal, then things will work.
else we will setup end up checking the wrong interpreter all over again.

[DonJayamanne]

Closing this as we have very few users on non-zmq and no one has run into this issue.