197.rising_temperature.md

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197.Rising Temperature

难度:Easy

给定一个 Weather 表，编写一个 SQL 查询，来查找与之前（昨天的）日期相比温度更高的所有日期的 Id。

+---------+------------------+------------------+
| Id(INT) | RecordDate(DATE) | Temperature(INT) |
+---------+------------------+------------------+
|       1 |       2015-01-01 |               10 |
|       2 |       2015-01-02 |               25 |
|       3 |       2015-01-03 |               20 |
|       4 |       2015-01-04 |               30 |
+---------+------------------+------------------+
例如，根据上述给定的 Weather 表格，返回如下 Id:

+----+
| Id |
+----+
|  2 |
|  4 |
+----+

需要認識DATEDIFF函數，主要是比較日期的，前者大返回1，後者大返回-1；

 Write your MySQL query statement below

SELECT
    weather.id AS 'Id'
FROM
    weather
        JOIN
    weather w ON DATEDIFF(weather.RecordDate, w.RecordDate) = 1
        AND weather.Temperature > w.Temperature
;

执行用时 :978 ms, 在所有 C++ 提交中击败了16.9%的用户
内存消耗 :N/A