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基于Canvas+Vue的弹幕组件
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2019-07-20
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<span id="/2019/07/20/Vue/Barrage/" class="leancloud_visitors" data-flag-title="基于Canvas+Vue的弹幕组件">
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<blockquote>
<p>最近由于项目需要定制化一个弹幕功能，所以尝试使用canvas来开发组件。经过测试在一些低端机的效果也没有明显的卡顿，和大家交流一下</p>
</blockquote>
<h3 id="弹幕效果"><a href="#弹幕效果" class="headerlink" title="弹幕效果"></a>弹幕效果</h3><p><img src="https://user-gold-cdn.xitu.io/2019/7/20/16c0f1a946a59f3e?w=480&h=188&f=gif&s=4517801" alt=""></p>
<h3 id="功能介绍"><a href="#功能介绍" class="headerlink" title="功能介绍"></a>功能介绍</h3><ul>
<li>支持循环弹幕</li>
<li>弹幕不重叠</li>
<li>支持选择轨道数</li>
<li>支持弹幕发送</li>
</ul>
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<a class="post-title-link" href="/2019/07/04/LeetCode/950/" itemprop="url">
LeetCode：950.按递增顺序显示卡牌
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<span class="post-meta-item-text">发表于</span>
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2019-07-04
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<span id="/2019/07/04/LeetCode/950/" class="leancloud_visitors" data-flag-title="LeetCode：950.按递增顺序显示卡牌">
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<p><strong>题目</strong></p>
<blockquote>
<p><a href="https://leetcode-cn.com/problems/reveal-cards-in-increasing-order/" target="_blank" rel="noopener">按递增顺序显示卡牌</a></p>
</blockquote>
<p><strong>描述</strong></p>
<h5 id="牌组中的每张卡牌都对应有一个唯一的整数。你可以按你想要的顺序对这套卡片进行排序。"><a href="#牌组中的每张卡牌都对应有一个唯一的整数。你可以按你想要的顺序对这套卡片进行排序。" class="headerlink" title="牌组中的每张卡牌都对应有一个唯一的整数。你可以按你想要的顺序对这套卡片进行排序。"></a>牌组中的每张卡牌都对应有一个唯一的整数。你可以按你想要的顺序对这套卡片进行排序。</h5><h5 id="最初，这些卡牌在牌组里是正面朝下的（即，未显示状态）。"><a href="#最初，这些卡牌在牌组里是正面朝下的（即，未显示状态）。" class="headerlink" title="最初，这些卡牌在牌组里是正面朝下的（即，未显示状态）。"></a>最初，这些卡牌在牌组里是正面朝下的（即，未显示状态）。</h5><h5 id="现在，重复执行以下步骤，直到显示所有卡牌为止："><a href="#现在，重复执行以下步骤，直到显示所有卡牌为止：" class="headerlink" title="现在，重复执行以下步骤，直到显示所有卡牌为止："></a>现在，重复执行以下步骤，直到显示所有卡牌为止：</h5><h5 id="从牌组顶部抽一张牌，显示它，然后将其从牌组中移出。如果牌组中仍有牌，则将下一张处于牌组顶部的牌放在牌组的底部。如果仍有未显示的牌，那么返回步骤-1。否则，停止行动。返回能以递增顺序显示卡牌的牌组顺序。"><a href="#从牌组顶部抽一张牌，显示它，然后将其从牌组中移出。如果牌组中仍有牌，则将下一张处于牌组顶部的牌放在牌组的底部。如果仍有未显示的牌，那么返回步骤-1。否则，停止行动。返回能以递增顺序显示卡牌的牌组顺序。" class="headerlink" title="从牌组顶部抽一张牌，显示它，然后将其从牌组中移出。如果牌组中仍有牌，则将下一张处于牌组顶部的牌放在牌组的底部。如果仍有未显示的牌，那么返回步骤 1。否则，停止行动。返回能以递增顺序显示卡牌的牌组顺序。"></a>从牌组顶部抽一张牌，显示它，然后将其从牌组中移出。如果牌组中仍有牌，则将下一张处于牌组顶部的牌放在牌组的底部。如果仍有未显示的牌，那么返回步骤 1。否则，停止行动。返回能以递增顺序显示卡牌的牌组顺序。</h5><h5 id="答案中的第一张牌被认为处于牌堆顶部。"><a href="#答案中的第一张牌被认为处于牌堆顶部。" class="headerlink" title="答案中的第一张牌被认为处于牌堆顶部。"></a>答案中的第一张牌被认为处于牌堆顶部。</h5>
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LeetCode：11.盛最多水的容器
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<p><strong>题目</strong></p>
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<p><a href="https://leetcode-cn.com/problems/container-with-most-water/" target="_blank" rel="noopener">盛最多水的容器</a></p>
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<p><strong>描述</strong></p>
<h6 id="给定-n-个非负整数-a1，a2，…，an，每个数代表坐标中的一个点-i-ai-。在坐标内画-n-条垂直线，垂直线-i-的两个端点分别为-i-ai-和-i-0-。找出其中的两条线，使得它们与-x-轴共同构成的容器可以容纳最多的水。"><a href="#给定-n-个非负整数-a1，a2，…，an，每个数代表坐标中的一个点-i-ai-。在坐标内画-n-条垂直线，垂直线-i-的两个端点分别为-i-ai-和-i-0-。找出其中的两条线，使得它们与-x-轴共同构成的容器可以容纳最多的水。" class="headerlink" title="给定 n 个非负整数 a1，a2，…，an，每个数代表坐标中的一个点 (i, ai) 。在坐标内画 n 条垂直线，垂直线 i 的两个端点分别为 (i, ai) 和 (i, 0)。找出其中的两条线，使得它们与 x 轴共同构成的容器可以容纳最多的水。"></a>给定 n 个非负整数 a1，a2，…，an，每个数代表坐标中的一个点 (i, ai) 。在坐标内画 n 条垂直线，垂直线 i 的两个端点分别为 (i, ai) 和 (i, 0)。找出其中的两条线，使得它们与 x 轴共同构成的容器可以容纳最多的水。</h6><blockquote>
<p>说明：你不能倾斜容器，且 n 的值至少为 2。</p>
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<p>本文转载自前端学习指南的<a href="https://zhuanlan.zhihu.com/p/22486908" target="_blank" rel="noopener">这篇文章</a>(写的很清晰易懂，实在不忍心修改)</p>
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<p><strong>《javascript高级程序设计》（第三版）第7章第2节：</strong></p>
<blockquote>
<p>闭包是指有权访问另一个函数作用域中的变量函数 </p>
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<p><strong>《javascript权威指南》(第六版)第8章第6节：</strong></p>
<blockquote>
<p>从技术的角度讲，所有的<code>JavaScript</code>函数都是闭包：它们都是对象，它们都关联到作用域链。 </p>
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<p><strong>本文作者的理解(当然我的理解和本文作者的理解是一样的)</strong></p>
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<p>「函数」和「函数内部能访问到的变量」(也叫环境)的总和，就是一个闭包。</p>
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