Serializing vector

[yuvalyo]

at this moment i'm working on a little project and i'm trying to serialize a vector

the current code is:

std::string JsonResponsePacketSerializer::serializeResponse(HighscoreResponse response)
{
	json j;
	j["status"] = response.status;
	j["highscores"] = {};
	for (auto iter = response.highscores.begin(); iter != response.highscores.end(); ++iter)
	{
		j["highscores"].push_back(*iter);
	}


	return j.dump();
}

as you can see in the struct the "highscores" is a vector
but i'm gettting all kind of erros such as:

1. could not find to_json() method in T's namespace
   2)forcing MSVC stacktrace to show which T we're talking about.

thanks for your help 👍

[nlohmann]

Please have a look at this section of the README: https://github.com/nlohmann/json/blob/develop/README.md#arbitrary-types-conversions

[yuvalyo]

so you say i just need to do like:

json j;
j["highscores"] = response.highscores;

?

[nlohmann]

You need to provide a to_json function.

[yuvalyo]

std::string JsonResponsePacketSerializer::serializeResponse(HighscoreResponse response)
{
	json j = json{ { "status", response.status },{ "highscores", response.highscores }};
	return j.dump();
}

still does not work

[nlohmann]

Can you provide the code of your to_json function?

[yuvalyo]

void to_json(json& j, const HighscoreResponse& response)
{
	j = json{ { "status", response.status },{ "highscores", response.highscores }};
}

this is my to_json function but i need to know just hot to serialize the vector because from what i understood you can only convert normal types and not user_defined

[theodelrieu]

Is the to_json function in the same namespace than HighscoreResponse?

If so, it means that some member of HighscoreResponse is a user defined type which also need a to_json function

[yuvalyo]

i just need to know how do you convert a std::vector to json

[nlohmann]

Given std::vector<Foo>, then it is sufficient to provide a to_json function for type Foo - the library then knows how to process a vector of Foo.

[nlohmann]

Do you need further assistance on this?