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73.py
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73.py
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'''
Given an m x n integer matrix matrix, if an element is 0, set its entire row and column to 0's.
You must do it in place.
Example 1:
Input: matrix = [[1,1,1],[1,0,1],[1,1,1]]
Output: [[1,0,1],[0,0,0],[1,0,1]]
Example 2:
Input: matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]
Output: [[0,0,0,0],[0,4,5,0],[0,3,1,0]]
Constraints:
m == matrix.length
n == matrix[0].length
1 <= m, n <= 200
-231 <= matrix[i][j] <= 231 - 1
Follow up:
A straightforward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?
'''
# https://leetcode.com/problems/set-matrix-zeroes/
import unittest
def setZeroes(matrix):
rows, cols = len(matrix), len(matrix[0])
is_col = False
for i in range(rows):
if matrix[i][0] == 0:
is_col = True
for j in range(1, cols):
if matrix[i][j] == 0:
matrix[i][0] = 0
matrix[0][j] = 0
for i in range(1, rows):
for j in range(1, cols):
if not matrix[i][0] or not matrix[0][j]:
matrix[i][j] = 0
if matrix[0][0] == 0:
for j in range(cols):
matrix[0][j] = 0
if is_col:
for i in range(rows):
matrix[i][0] = 0
return matrix
class TestSetMatrixZeroes(unittest.TestCase):
def test_example1(self):
matrix = [[1, 1, 1], [1, 0, 1], [1, 1, 1]]
expected = [[1, 0, 1], [0, 0, 0], [1, 0, 1]]
# Call the function that solves the problem
result = setZeroes(matrix)
# Assert that the result matches the expected output
self.assertEqual(result, expected)
def test_example2(self):
matrix = [[0, 1, 2, 0], [3, 4, 5, 2], [1, 3, 1, 5]]
expected = [[0, 0, 0, 0], [0, 4, 5, 0], [0, 3, 1, 0]]
# Call the function that solves the problem
result = setZeroes(matrix)
# Assert that the result matches the expected output
self.assertEqual(result, expected)
if __name__ == '__main__':
unittest.main()