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What is the |
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Final version option 2️⃣ server
.WhenRequest(r => r //⚡ The Request.Create() has been replaced by an Action
.WithPath("/mypath")
.UsingPost()
)
.DefineGuid("86984b0e-2516-4935-a2ef-b45bf4820d7d") //⚡ An extra method DefineGuid is added
.ThenRespondWith(r => r //⚡ The Response.Create() has been replaced by an Action
.WithHeader("Content-Type", "application/json")
.WithBodyAsJson("{{JsonPath.SelectToken request.body \"..name\"}}")
.WithTransformer()
.WithStatusCode(HttpStatusCode.Accepted)
); |
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PR #1042 has been merged. A new version 1.6.0 will be released in some days |
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Currently the C# code to build a request with a response is like:
I want to make this a bit easier to use.
1️⃣
My first proposal is like this:
2️⃣
Optionally, my second proposal could be to use
WhenRequest
, so:3️⃣
Optionally, option 3,
RespondWith
is replaced byRespond
:Also another change would be that in case you just want a simple 200 ok response, you can now use:
or
(#1042)
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