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There was a problem with the type parser such that the token nil would be accepted as a type, and give the same result as (). So you could declare a function signature to be f: nil -> bool.
This is not legal and the change removes the error.
(originally filed by @nickbattle, moved by me when issues were re-created)
The text was updated successfully, but these errors were encountered:
There was a problem with the type parser such that the token
nil
would be accepted as a type, and give the same result as()
. So you could declare a function signature to bef: nil -> bool
.This is not legal and the change removes the error.
(originally filed by @nickbattle, moved by me when issues were re-created)
The text was updated successfully, but these errors were encountered: