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page 222, equation 6.22, 3rd edition #15

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ryanyu512 opened this issue Feb 15, 2024 · 1 comment
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page 222, equation 6.22, 3rd edition #15

ryanyu512 opened this issue Feb 15, 2024 · 1 comment
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@ryanyu512
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Yz = [1_mm, 0_mx;
Gx, 0_2*(M-3), Gz)

If M = 0, then M - 3 is negative. It seems confusing

@petercorke
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Thanks for picking this up. This is insertion Jacobian for the SLAM case, for the landmark-only case there should be no ${\bf G}_x$ and the zeros after it should be ${\bf 0}_{2 \times M}$

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