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Copy path13A15-ProofOfFiniteExtensionsOfDedekindDomainsAreDedekind.tex
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13A15-ProofOfFiniteExtensionsOfDedekindDomainsAreDedekind.tex
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\documentclass[12pt]{article}
\usepackage{pmmeta}
\pmcanonicalname{ProofOfFiniteExtensionsOfDedekindDomainsAreDedekind}
\pmcreated{2013-03-22 18:35:44}
\pmmodified{2013-03-22 18:35:44}
\pmowner{gel}{22282}
\pmmodifier{gel}{22282}
\pmtitle{proof of finite extensions of Dedekind domains are Dedekind}
\pmrecord{4}{41325}
\pmprivacy{1}
\pmauthor{gel}{22282}
\pmtype{Proof}
\pmcomment{trigger rebuild}
\pmclassification{msc}{13A15}
\pmclassification{msc}{13F05}
%\pmkeywords{Dedekind domain}
%\pmkeywords{finite extension}
%\pmkeywords{separable}
%\pmkeywords{purely inseparable}
\endmetadata
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\begin{document}
Let $R$ be a Dedekind domain with field of fractions $K$. If $L/K$ is a finite extension of fields and $A$ is the integral closure of $R$ in $L$, then we show that $A$ is also a Dedekind domain.
We procede by splitting the proof up into the separable and purely inseparable cases. Letting $F$ consist of all elements of $L$ which are separable over $K$, then $F/K$ is a separable extension and $L/F$ is a purely inseparable extension.
First, the integral closure $B$ of $R$ in $F$ is a Dedekind domain (see proof of finite separable extensions of Dedekind domains are Dedekind). Then, as $A$ is integrally closed and contains $B$, it is equal to the integral closure of $B$ in $L$ and, therefore, is a Dedekind domain (see proof of finite inseparable extensions of Dedekind domains are Dedekind).
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\end{document}