Implement Store.add_image()

[augustebaum]

See #77 (comment)

Currently the dashboard accepts images in form of a base64-encoded with a mime-type (supported formats are SVG, PNG, JPEG and WEBP). However, there is currently no way of saving an image in a Mandr that could then be sent to the dashboard.

One issue is that we're unsure of how to detect the image's format, so we'd require the user to specify it manually every time.

All this to say, the design still needs to be specified.

---

For context, initially this issue was meant to help implement saving a Matplotlib, which would look something like this:

fig, ax = plt.subplots()

...

mandr.add_matplotlib(fig)

and be implemented something like this:

def insert_matplotlib(self, fig):
    figure_file = StringIO()
    fig.savefig(figure_file, format="svg")
    self.add_image(figure_file.getvalue(), type="image/svg+xml")

[thomass-dev]

Don't think this issue is mandatory here, it will come in #50 .
Adding a new image type in the JSON schema between mandr and dashboard is good ( #77 ).

[augustebaum]

I opened the issue now to make sure that we have a reference to #77 (comment), which will guide the implementation

[tuscland]

Is this still relevant? What is the feature behind this? Please specify the context in the issue.

[augustebaum]

Added some context in the issue description

[rouk1]

Pillow detects the format of an opened Image.

It should help to detect the mime-type.

[tuscland]

From our discussion there are several issues here:

• What you put is what you get: we should not modify the things at insertion.
• Display type inference: the intelligence about how an item should be displayed should be done lazily at display time
• Storing (only) pickled objects, cause a serious problem of interoperability: more specifically, how we maintain the compatibility with user specified libraries, for example in a platform/server environment?

[tuscland]

Closing, because a workaround has been implemented.

Also most of the issues discussed in the previous message will be solved by #303