title | aliases | summary | ||
---|---|---|---|---|
控制流程函数 |
|
TiDB 支持 MySQL 8.0 中的控制流程函数,包括 CASE、IF()、IFNULL() 和 NULLIF()。这些函数可以用于构建 if/else 语句和处理 NULL 值。 |
TiDB 支持使用 MySQL 8.0 中提供的所有控制流程函数。
函数名 | 功能描述 |
---|---|
CASE |
Case 操作符 |
IF() |
构建 if/else |
IFNULL() |
构建 Null if/else |
NULLIF() |
如果 expr1 = expr2,返回 NULL |
CASE
操作符可以根据指定的条件进行条件逻辑判断并自定义查询结果。
语法:
CASE
WHEN condition1 THEN result1
WHEN condition2 THEN result2
...
ELSE default_result
END
示例:
WITH RECURSIVE d AS (SELECT 1 AS n UNION ALL SELECT n+1 FROM d WHERE n<10)
SELECT n, CASE WHEN n MOD 2 THEN "odd" ELSE "even" END FROM d;
+----+----------------------------------------------+
| n | CASE WHEN n MOD 2 THEN "odd" ELSE "even" END |
+----+----------------------------------------------+
| 1 | odd |
| 2 | even |
| 3 | odd |
| 4 | even |
| 5 | odd |
| 6 | even |
| 7 | odd |
| 8 | even |
| 9 | odd |
| 10 | even |
+----+----------------------------------------------+
10 rows in set (0.00 sec)
IF()
函数可以根据值或表达式是否为真执行不同的操作。
语法:
IF(condition, value_if_true, value_if_false)
示例:
WITH RECURSIVE d AS (SELECT 1 AS n UNION ALL SELECT n+1 FROM d WHERE n<10)
SELECT n, IF(n MOD 2, "odd", "even") FROM d;
+----+----------------------------+
| n | IF(n MOD 2, "odd", "even") |
+----+----------------------------+
| 1 | odd |
| 2 | even |
| 3 | odd |
| 4 | even |
| 5 | odd |
| 6 | even |
| 7 | odd |
| 8 | even |
| 9 | odd |
| 10 | even |
+----+----------------------------+
10 rows in set (0.00 sec)
IFNULL(expr1,expr2)
函数用于处理查询中的 NULL 值。如果 expr1
不为 NULL
,该函数返回 expr1
;否则返回 expr2
。
示例:
WITH data AS (SELECT NULL AS x UNION ALL SELECT 1 )
SELECT x, IFNULL(x,'x has no value') FROM data;
+------+----------------------------+
| x | IFNULL(x,'x has no value') |
+------+----------------------------+
| NULL | x has no value |
| 1 | 1 |
+------+----------------------------+
2 rows in set (0.0006 sec)
NULLIF(expr1,expr2)
函数用于在两个参数相同或第一个参数为 NULL
时返回 NULL
。否则,返回第一个参数。
示例:
WITH RECURSIVE d AS (SELECT 1 AS n UNION ALL SELECT n+1 FROM d WHERE n<10)
SELECT n, NULLIF(n+n, n+2) FROM d;
+----+------------------+
| n | NULLIF(n+n, n+2) |
+----+------------------+
| 1 | 2 |
| 2 | NULL |
| 3 | 6 |
| 4 | 8 |
| 5 | 10 |
| 6 | 12 |
| 7 | 14 |
| 8 | 16 |
| 9 | 18 |
| 10 | 20 |
+----+------------------+
10 rows in set (0.00 sec)
在该示例中,当 n
等于 2
时,n+n
和 n+2
都等于 4
,两个参数值相同,因此函数返回 NULL
。