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Copy file name to clipboardexpand all lines: docs/versioned_docs/version-v111/intro.md
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@@ -84,7 +84,7 @@ There is no need to set the `Content-Type` or add the `DataFormat` parameter to
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RestSharp will also handle both XML and JSON responses and perform all necessary deserialization tasks, depending on the server response type. Therefore, you only need to add the `Accept` header if you want to deserialize the response manually.
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For example, only you'd only need these lines to make a request with JSON body:
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For example, you'd only need these lines to make a request with JSON body:
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