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rqalpha的2.1.4
python 2.x
问题描述: 在了使用 生成的pkl文件进行画图的时候,报找不到pkl文件的问题,希望得到解答,谢谢。 在使用 0.3.x版本的时候,这个功能还是很正常的
在Windows和Linux都尝试过
我的执行命令
rqalpha plot ./1.pkl --show
错误日志
Traceback (most recent call last): File "c:\programdata\anaconda2\lib\runpy.py", line 174, in _run_module_as_main "__main__", fname, loader, pkg_name) File "c:\programdata\anaconda2\lib\runpy.py", line 72, in _run_code exec code in run_globals │ └ {'__builtins__': <module '__builtin__' (built-in)>, '__file__': 'C:\ProgramData\Anaconda2\Scripts\rqalpha.exe\__main__.py',... qalpha.exe\__main__.py", line 2>> at 0256EA40, file "C:\ProgramData\Anaconda2\Scripts File "C:\ProgramData\Anaconda2\Scripts\rqalpha.exe\__main__.py", line 9, in <module> sys.exit(entry_point()) │ └ <function entry_point at 0x047D1CF0> └ <module 'sys' (built-in)> File "c:\programdata\anaconda2\lib\site-packages\rqalpha\__main__.py", line 66, in entry_point cli(obj={}) └ <click.core.Group object at 0x047CFE90> File "c:\programdata\anaconda2\lib\site-packages\click\core.py", line 722, in __call__ return self.main(*args, **kwargs) │ │ └ {'obj': {'VERBOSE': 0}} │ └ () └ <click.core.Group object at 0x047CFE90> File "c:\programdata\anaconda2\lib\site-packages\click\core.py", line 697, in main rv = self.invoke(ctx) │ └ <click.core.Context object at 0x0482CC10> └ <click.core.Group object at 0x047CFE90> File "c:\programdata\anaconda2\lib\site-packages\click\core.py", line 1066, in invoke return _process_result(sub_ctx.command.invoke(sub_ctx)) │ │ └ <click.core.Context object at 0x0482CE50> │ └ <click.core.Context object at 0x0482CE50> └ <function _process_result at 0x0482D5B0> File "c:\programdata\anaconda2\lib\site-packages\click\core.py", line 895, in invoke return ctx.invoke(self.callback, **ctx.params) │ │ └ <click.core.Context object at 0x0482CE50> │ └ <click.core.Command object at 0x0482CF50> └ <click.core.Context object at 0x0482CE50> File "c:\programdata\anaconda2\lib\site-packages\click\core.py", line 535, in invoke return callback(*args, **kwargs) │ │ └ {'result_pickle_file_path': u'./1.pkl', 'plot_save_file': None, 'show': True} │ └ () └ <function plot at 0x0482D830> TypeError: plot() got an unexpected keyword argument 'result_pickle_file_path'
The text was updated successfully, but these errors were encountered:
确认是个bug
在 rqlpah/mod/rqalpha_mod_sys_analyser/__init__.py 文件中
rqlpah/mod/rqalpha_mod_sys_analyser/__init__.py
@cli.command() @click.argument('result_pickle_file_path', type=click.Path(exists=True), required=True) @click.option('--show/--hide', 'show', default=True) @click.option('--plot-save', 'plot_save_file', default=None, type=click.Path(), help="save plot result to file") def plot(result_dict_file, show, plot_save_file): """ [sys_analyser] draw result DataFrame """ import pandas as pd from .plot import plot_result result_dict = pd.read_pickle(result_dict_file) plot_result(result_dict, show, plot_save_file)
其中 plot 的函数输入参数有误,应该改为 result_pickle_file_path
plot
result_pickle_file_path
Sorry, something went wrong.
@xtsfullstack 已修复并提交到develop 分支 下一个版本会发布会修复这个问题
32e70a0
2.2.0 已发布
wh1100717
No branches or pull requests
rqalpha的2.1.4
python 2.x
问题描述:
在了使用 生成的pkl文件进行画图的时候,报找不到pkl文件的问题,希望得到解答,谢谢。
在使用 0.3.x版本的时候,这个功能还是很正常的
在Windows和Linux都尝试过
我的执行命令
错误日志
The text was updated successfully, but these errors were encountered: