Compress_the_String!.py

# In this task, we would like for you to appreciate the usefulness of the groupby() function of itertools . To read more about this function, Check this out .

# You are given a string . Suppose a character '' occurs consecutively  times in the string. Replace these consecutive occurrences of the character '' with  in the string.

# For a better understanding of the problem, check the explanation.

# Input Format

# A single line of input consisting of the string .

# Output Format

# A single line of output consisting of the modified string.

# Constraints

# All the characters of  denote integers between  and .


# Sample Input

# 1222311
# Sample Output

# (1, 1) (3, 2) (1, 3) (2, 1)
# Explanation

# First, the character  occurs only once. It is replaced by . Then the character  occurs three times, and it is replaced by  and so on.

# Also, note the single space within each compression and between the compressions.

# Enter your code here. Read input from STDIN. Print output to STDOUT
s = input()
bef = s[0]
cou = 0
for i in s:
    if i == bef:
        cou+=1
    else:
        print((cou,int(bef)),end=" ")
        bef = i
        cou=1
print((cou,int(bef)),end=" ")