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@travissarles travissarles mentioned this pull request Apr 5, 2017
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previous-page: operators
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_By-name parameters_ are only evaluated when used. They are in contrast to _by-value parameters_. To make a parameter called by value, simply prepend `=>` to its type.
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"To make a parameter called by name", you mean

_By-name parameters_ are only evaluated when used. They are in contrast to _by-value parameters_. To make a parameter called by value, simply prepend `=>` to its type.

```tut
def goToSleep(tired: Boolean, seconds: => Int) = if (tired) Thread.sleep(seconds)
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too long for a one-liner, especially given the site layout

def lengthOfNap = 3600 * 8
goToSleep(tired = false, seconds = lengthOfNap)
```
The type of `seconds` is `=> Int` which means `seconds` is a by-name parameter. Therefore, when we call `goToSleep` it with `tired = false`, `lengthOfNap` will not be evaluated.
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This is not that compelling of an example. I would suggest leading with an example where avoiding unwanted evaluation is actually crucial. Computing a number of seconds is highly unlikely to be an expensive computation.

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What did you see as the downsides with the examples in the original version...?

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Looking back at the original example, it does look better. I'll put it back.

@travissarles travissarles force-pushed the by-name-params branch 2 times, most recently from 9f48bbf to 9f8df37 Compare April 10, 2017 14:17
i -= 1
} // prints 2 1
```
The method `whileLoop` uses multiple parameter lists to take a condition and a body of the loop. If the `condition` is true, the `body` is executed and then a recursive call to whileLoop is made. If the `condition` is false, the body is never evaluated because we prepended `=>` to the return type.
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=> wasn't appended to the return type; it was appended to body's type.

```
The method `whileLoop` uses multiple parameter lists to take a condition and a body of the loop. If the `condition` is true, the `body` is executed and then a recursive call to whileLoop is made. If the `condition` is false, the body is never evaluated because we prepended `=>` to the return type.

Now when we pass `i > 0` as our `condition` and `println(i); i-= 1` as the `body`, it behaves like the standard while loop in many languages. Here is the output:
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Where is it?

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I'll remove that sentence since I have the output in a comment.

@travissarles travissarles merged commit d915d25 into scala:master May 12, 2017
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3 participants