Produces Non-Compiling Code with implicit keyword after colon

[dallinhuff]

Configuration

version = 3.7.17
runner.dialect = scala3

Command-line parameters

When I run scalafmt via CLI like this: scalafmt .

Steps

Given code like this:

def runJs: CancelableFuture[A] =
  Unsafe.unsafe:
    implicit unsafe =>
      Runtime.default.unsafe
        .runToFuture(zio.provide(BackendClientLive.configuredLayer))

Problem

Scalafmt formats code like this:

def runJs: CancelableFuture[A] =
  Unsafe.unsafe: implicit unsafe =>
    Runtime.default.unsafe
      .runToFuture(zio.provide(BackendClientLive.configuredLayer))

The formatted code no longer compiles because the next token after the colon in Unsafe.unsafe: needs to be either a newline/significant indentation or an identifier. The implicit keyword is neither of these.

Expectation

I would like the formatted output to look like this, since it compiles:

def runJs: CancelableFuture[A] =
  Unsafe.unsafe:
    implicit unsafe =>
      Runtime.default.unsafe
        .runToFuture(zio.provide(BackendClientLive.configuredLayer))

[kitbellew]

@dallinhuff could you please show which part of syntax allows implicit (or anything other than erased) in ColonArgument?

[dallinhuff]

@kitbellew Looks like this might have been an issue with someone (manually) rewriting some old Scala 2 to use fewerBraces. Rewriting implicit id => ... as a context function id ?=> ... seems to fix the problem and scalafmt handles this as expected.

def runJs: CancelableFuture[A] =
  Unsafe.unsafe: unsafe ?=>
    Runtime.default.unsafe
      .runToFuture(zio.provide(BackendClientLive.configuredLayer))