Question 27

Author: shubhamkumar27

27. Remove Element.py

@@ -0,0 +1,44 @@
+'''
+Given an array nums and a value val, remove all instances of that value in-place and 
+return the new length.
+Do not allocate extra space for another array, you must do this by modifying the input 
+array in-place with O(1) extra memory.
+The order of elements can be changed. It doesn't matter what you leave beyond the new length.
+
+Example 1:
+Given nums = [3,2,2,3], val = 3,
+Your function should return length = 2, with the first two elements of nums being 2.
+It doesn't matter what you leave beyond the returned length.
+
+Example 2:
+Given nums = [0,1,2,2,3,0,4,2], val = 2,
+Your function should return length = 5, with the first five elements of nums containing 
+0, 1, 3, 0, and 4.
+Note that the order of those five elements can be arbitrary.
+
+It doesn't matter what values are set beyond the returned length.
+
+Clarification:
+Confused why the returned value is an integer but your answer is an array?
+Note that the input array is passed in by reference, which means modification to the 
+input array will be known to the caller as well.
+Internally you can think of this:
+
+// nums is passed in by reference. (i.e., without making a copy)
+int len = removeElement(nums, val);
+
+// any modification to nums in your function would be known by the caller.
+// using the length returned by your function, it prints the first len elements.
+for (int i = 0; i < len; i++) {
+    print(nums[i]);
+}
+'''
+
+class Solution:
+    def removeElement(self, nums, val):
+        l = 0
+        for i in range(len(nums)):
+            if nums[i]!=val:
+                nums[l]=nums[i]
+                l += 1
+        return l