forked from bonfy/leetcode
-
Notifications
You must be signed in to change notification settings - Fork 1
/
Copy pathh-index-ii.py
46 lines (41 loc) · 1.47 KB
/
h-index-ii.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
# -*- coding:utf-8 -*-
# Given an array of citations sorted in ascending order (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's h-index.
#
# According to the definition of h-index on Wikipedia: "A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each."
#
# Example:
#
#
# Input: citations = [0,1,3,5,6]
# Output: 3
# Explanation: [0,1,3,5,6] means the researcher has 5 papers in total and each of them had
# received 0, 1, 3, 5, 6 citations respectively.
# Since the researcher has 3 papers with at least 3 citations each and the remaining
# two with no more than 3 citations each, her h-index is 3.
#
# Note:
#
# If there are several possible values for h, the maximum one is taken as the h-index.
#
# Follow up:
#
#
# This is a follow up problem to H-Index, where citations is now guaranteed to be sorted in ascending order.
# Could you solve it in logarithmic time complexity?
#
#
class Solution(object):
def hIndex(self, citations):
"""
:type citations: List[int]
:rtype: int
"""
n = len(citations)
l, r = 0, n-1
while l <= r:
mid = (l+r)/2
if citations[mid] >= n-mid:
r = mid - 1
else:
l = mid + 1
return n-l