-
Notifications
You must be signed in to change notification settings - Fork 2
/
Copy pathDay-31-Climbing Stairs.cpp
79 lines (47 loc) · 1.16 KB
/
Day-31-Climbing Stairs.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Example 1:
Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Example 2:
Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
Constraints:
1 <= n <= 45
Hide Hint #1
To reach nth step, what could have been your previous steps? (Think about the step sizes)
// recursive (TLE)
class Solution {
public:
int rec(int n){
if(n<=1) return 1; // Only one way to reach
return rec(n-1) + rec(n-2);
}
int climbStairs(int n) {
return rec(n);
}
};
// Memoization
class Solution {
public:
int rec(int n, int dp[]){
if(n<=1) return 1;
if(dp[n]!=-1) return dp[n];
dp[n-1]=rec(n-1, dp);
dp[n-2]=rec(n-2, dp);
dp[n]=dp[n-1]+dp[n-2];
return dp[n];
}
int climbStairs(int n) {
int dp[n+1];
fill(dp, dp+n+1, -1);
return rec(n, dp);
}
};