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2087. Minimum Cost Homecoming of a Robot in a Grid: RETRY
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src/solution/mod.rs

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@@ -1573,3 +1573,4 @@ mod s2080_range_frequency_queries;
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mod s2081_sum_of_k_mirror_numbers;
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mod s2085_count_common_words_with_one_occurrence;
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mod s2086_minimum_number_of_food_buckets_to_feed_the_hamsters;
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mod s2087_minimum_cost_homecoming_of_a_robot_in_a_grid;
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/**
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* [2087] Minimum Cost Homecoming of a Robot in a Grid
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*
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* There is an m x n grid, where (0, 0) is the top-left cell and (m - 1, n - 1) is the bottom-right cell. You are given an integer array startPos where startPos = [startrow, startcol] indicates that initially, a robot is at the cell (startrow, startcol). You are also given an integer array homePos where homePos = [homerow, homecol] indicates that its home is at the cell (homerow, homecol).
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* The robot needs to go to its home. It can move one cell in four directions: left, right, up, or down, and it can not move outside the boundary. Every move incurs some cost. You are further given two 0-indexed integer arrays: rowCosts of length m and colCosts of length n.
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*
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* If the robot moves up or down into a cell whose row is r, then this move costs rowCosts[r].
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* If the robot moves left or right into a cell whose column is c, then this move costs colCosts[c].
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*
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* Return the minimum total cost for this robot to return home.
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*
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* Example 1:
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* <img alt="" src="https://assets.leetcode.com/uploads/2021/10/11/eg-1.png" style="width: 282px; height: 217px;" />
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* Input: startPos = [1, 0], homePos = [2, 3], rowCosts = [5, 4, 3], colCosts = [8, 2, 6, 7]
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* Output: 18
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* Explanation: One optimal path is that:
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* Starting from (1, 0)
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* -> It goes down to (<u>2</u>, 0). This move costs rowCosts[2] = 3.
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* -> It goes right to (2, <u>1</u>). This move costs colCosts[1] = 2.
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* -> It goes right to (2, <u>2</u>). This move costs colCosts[2] = 6.
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* -> It goes right to (2, <u>3</u>). This move costs colCosts[3] = 7.
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* The total cost is 3 + 2 + 6 + 7 = 18
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* Example 2:
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*
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* Input: startPos = [0, 0], homePos = [0, 0], rowCosts = [5], colCosts = [26]
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* Output: 0
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* Explanation: The robot is already at its home. Since no moves occur, the total cost is 0.
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*
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*
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* Constraints:
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*
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* m == rowCosts.length
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* n == colCosts.length
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* 1 <= m, n <= 10^5
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* 0 <= rowCosts[r], colCosts[c] <= 10^4
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* startPos.length == 2
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* homePos.length == 2
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* 0 <= startrow, homerow < m
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* 0 <= startcol, homecol < n
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*
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*/
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pub struct Solution {}
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// problem: https://leetcode.com/problems/minimum-cost-homecoming-of-a-robot-in-a-grid/
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// discuss: https://leetcode.com/problems/minimum-cost-homecoming-of-a-robot-in-a-grid/discuss/?currentPage=1&orderBy=most_votes&query=
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// submission codes start here
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impl Solution {
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pub fn min_cost(
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start_pos: Vec<i32>,
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home_pos: Vec<i32>,
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row_costs: Vec<i32>,
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col_costs: Vec<i32>,
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) -> i32 {
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0
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}
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}
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// submission codes end
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#[cfg(test)]
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mod tests {
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use super::*;
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#[test]
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#[ignore]
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fn test_2087_example_1() {
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let start_pos = vec![0, 0];
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let home_pos = vec![2, 3];
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let row_costs = vec![5, 4, 3];
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let col_costs = vec![8, 2, 6, 7];
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let result = 2;
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assert_eq!(
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Solution::min_cost(start_pos, home_pos, row_costs, col_costs),
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result
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);
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}
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#[test]
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#[ignore]
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fn test_2087_example_2() {
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let start_pos = vec![1, 0];
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let home_pos = vec![0, 0];
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let row_costs = vec![5];
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let col_costs = vec![26];
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let result = 18;
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assert_eq!(
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Solution::min_cost(start_pos, home_pos, row_costs, col_costs),
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result
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);
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}
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}

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