1sept22arithmetic.js

Given two numbers and an arithmetic operator (the name of it, as a string), return the result of the two numbers having that operator used on them.

a and b will both be positive integers, and a will always be the first number in the operation, and b always the second.

The four operators are "add", "subtract", "divide", "multiply".

A few examples:(Input1, Input2, Input3 --> Output)

5, 2, "add"      --> 7
5, 2, "subtract" --> 3
5, 2, "multiply" --> 10
5, 2, "divide"   --> 2.5

Try to do it without using if statements!


function arithmetic(a, b, operator){
    return operator == 'add'? a + b:
    operator == 'subtract' ? a - b:
    operator == 'multiply'? a * b:
    a/b
   }

   switch(operator){
       case 'add': return a+b;
       break;
       case 'subtract': return a-b;
       break;
       case 'multiply' : return a*b;
       break;
       default: return a/b

   }

   //another way to do it:
   const arithmetic = (a, b, operator) => ({
    'add'     : a + b,
    'subtract': a - b,
    'multiply': a * b,
    'divide'  : a / b
  }[operator]);

  {conditionals}[parametere]