Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no "holes" between ranks.
+----+-------+ | Id | Score | +----+-------+ | 1 | 3.50 | | 2 | 3.65 | | 3 | 4.00 | | 4 | 3.85 | | 5 | 4.00 | | 6 | 3.65 | +----+-------+
For example, given the above Scores
table, your query should generate the following report (order by highest score):
+-------+---------+ | score | Rank | +-------+---------+ | 4.00 | 1 | | 4.00 | 1 | | 3.85 | 2 | | 3.65 | 3 | | 3.65 | 3 | | 3.50 | 4 | +-------+---------+
Important Note: For MySQL solutions, to escape reserved words used as column names, you can use an apostrophe before and after the keyword. For example `Rank`.
Use DENSE_RANK()
to solve this problem.
DENSE_RANK() OVER (
PARTITION BY <expression>[{,<expression>...}]
ORDER BY <expression> [ASC|DESC], [{,<expression>...}]
)
Solution:
# Write your MySQL query statement below
SELECT Score, DENSE_RANK() OVER (ORDER BY Score DESC) 'Rank'
FROM Scores;
MySQL only provides window function after version 8. In previous versions, variables can be used to achieve similar functions:
SELECT Score,
CONVERT(rk, SIGNED) `Rank`
FROM (SELECT Score,
IF(@latest = Score, @rank, @rank := @rank + 1) rk,
@latest := Score
FROM Scores,
(SELECT @rank := 0, @latest := NULL) tmp
ORDER BY Score DESC) s;