Given an array arr
, replace every element in that array with the greatest element among the elements to its right, and replace the last element with -1
.
After doing so, return the array.
Example 1:
Input: arr = [17,18,5,4,6,1] Output: [18,6,6,6,1,-1] Explanation: - index 0 --> the greatest element to the right of index 0 is index 1 (18). - index 1 --> the greatest element to the right of index 1 is index 4 (6). - index 2 --> the greatest element to the right of index 2 is index 4 (6). - index 3 --> the greatest element to the right of index 3 is index 4 (6). - index 4 --> the greatest element to the right of index 4 is index 5 (1). - index 5 --> there are no elements to the right of index 5, so we put -1.
Example 2:
Input: arr = [400] Output: [-1] Explanation: There are no elements to the right of index 0.
Constraints:
1 <= arr.length <= 104
1 <= arr[i] <= 105
class Solution:
def replaceElements(self, arr: List[int]) -> List[int]:
m = -1
for i in range(len(arr) - 1, -1, -1):
t = arr[i]
arr[i] = m
m = max(m, t)
return arr
class Solution {
public int[] replaceElements(int[] arr) {
for (int i = arr.length - 1, max = -1; i >= 0; --i) {
int t = arr[i];
arr[i] = max;
max = Math.max(max, t);
}
return arr;
}
}