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中文文档

Description

Table: Employee

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| employee_id   | int     |
| team_id       | int     |
+---------------+---------+
employee_id is the primary key for this table.
Each row of this table contains the ID of each employee and their respective team.

Write an SQL query to find the team size of each of the employees.

Return result table in any order.

The query result format is in the following example:

Employee Table:
+-------------+------------+
| employee_id | team_id    |
+-------------+------------+
|     1       |     8      |
|     2       |     8      |
|     3       |     8      |
|     4       |     7      |
|     5       |     9      |
|     6       |     9      |
+-------------+------------+
Result table:
+-------------+------------+
| employee_id | team_size  |
+-------------+------------+
|     1       |     3      |
|     2       |     3      |
|     3       |     3      |
|     4       |     1      |
|     5       |     2      |
|     6       |     2      |
+-------------+------------+
Employees with Id 1,2,3 are part of a team with team_id = 8.
Employees with Id 4 is part of a team with team_id = 7.
Employees with Id 5,6 are part of a team with team_id = 9.

Solutions

SQL

Solution 1:

# Write your MySQL query statement below
SELECT
    e.employee_id, t.team_size
FROM
    Employee e
LEFT JOIN
    (SELECT
        team_id, count(1) as team_size
    FROM
        Employee
    GROUP BY
        team_id
    ) t
ON
    e.team_id = t.team_id;

Solution 2:

# Write your MySQL query statement below
SELECT
    e1.employee_id, count(*) as team_size
FROM
    Employee e1
LEFT JOIN
    Employee e2
ON
    e1.team_id = e2.team_id
GROUP BY
    e1.employee_id;