README_EN.md

1805. Number of Different Integers in a String

中文文档

Description

You are given a string word that consists of digits and lowercase English letters.

You will replace every non-digit character with a space. For example, "a123bc34d8ef34" will become " 123  34 8  34". Notice that you are left with some integers that are separated by at least one space: "123", "34", "8", and "34".

Return the number of different integers after performing the replacement operations on word.

Two integers are considered different if their decimal representations without any leading zeros are different.

 

Example 1:

Input: word = "a123bc34d8ef34"
Output: 3
Explanation: The three different integers are "123", "34", and "8". Notice that "34" is only counted once.

Example 2:

Input: word = "leet1234code234"
Output: 2

Example 3:

Input: word = "a1b01c001"
Output: 1
Explanation: The three integers "1", "01", and "001" all represent the same integer because
the leading zeros are ignored when comparing their decimal values.

 

Constraints:

• 1 <= word.length <= 1000
• word consists of digits and lowercase English letters.

Solutions

Python3

import re

class Solution:
    def numDifferentIntegers(self, word: str) -> int:
        nums = re.split(r'[a-z]+', word)
        return len({int(num) for num in nums if num != ''})

Java

class Solution {
    public int numDifferentIntegers(String word) {
        String[] nums = word.split("[a-z]+");
        Set<String> numSet = new HashSet<>();
        for (String num : nums) {
            if ("".equals(num)) {
                continue;
            }
            int j = 0;
            while (j < num.length() - 1 && num.charAt(j) == '0') {
                ++j;
            }
            numSet.add(num.substring(j));
        }
        return numSet.size();
    }
}

...