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Hello,
I read your blog post about FAST-LIO and I have some questions about formula (28) $Exp(E)Exp(A(E)^T\Delta E) = d^{-1}\cdot a \cdot Exp(b)Exp(A(b)^T\Delta b)\cdot Exp(c)$
From, $Exp(E) = d^{-1}\cdot a \cdot Exp(b) \cdot Exp(c) $
We can write $Exp(E) \cdot Exp^{-1}(c) = d^{-1} \cdot a \cdot Exp(b)$
But in you blog post, It is written $Exp(A(E)^T\Delta E) = Exp(-c)Exp(A(b)^T\Delta b)\cdot Exp(c)$
Is it possible to use $Exp^{-1}(c)$ as a $Exp(-c)$ ?
The text was updated successfully, but these errors were encountered:
Hello,
$Exp(E)Exp(A(E)^T\Delta E) = d^{-1}\cdot a \cdot Exp(b)Exp(A(b)^T\Delta b)\cdot Exp(c)$
I read your blog post about FAST-LIO and I have some questions about formula (28)
From,$Exp(E) = d^{-1}\cdot a \cdot Exp(b) \cdot Exp(c) $ $Exp(E) \cdot Exp^{-1}(c) = d^{-1} \cdot a \cdot Exp(b)$
We can write
Therefore,$Exp(E)Exp(A(E)^T\Delta E) = Exp(E) \cdot Exp^{-1}(c)Exp(A(b)^T\Delta b)\cdot Exp(c)$
$\therefore Exp(A(E)^T\Delta E) = Exp^{-1}(c)Exp(A(b)^T\Delta b)\cdot Exp(c)$
But in you blog post, It is written$Exp(A(E)^T\Delta E) = Exp(-c)Exp(A(b)^T\Delta b)\cdot Exp(c)$ $Exp^{-1}(c)$ as a $Exp(-c)$ ?
Is it possible to use
The text was updated successfully, but these errors were encountered: