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Add solution and test-cases for problem 3043 #991

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Original file line number Diff line number Diff line change
@@ -1,28 +1,36 @@
# [3043.Find the Length of the Longest Common Prefix][title]

> [!WARNING|style:flat]
> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)

## Description
You are given two arrays with **positive** integers `arr1` and `arr2`.

A **prefix** of a positive integer is an integer formed by one or more of its digits, starting from its **leftmost** digit. For example, `123` is a prefix of the integer `12345`, while `234` is **not**.

A **common prefix** of two integers `a` and `b` is an integer `c`, such that `c` is a prefix of both `a` and `b`. For example, `5655359` and `56554` have a common prefix `565` while `1223` and `43456` do not have a common prefix.

You need to find the length of the **longest common prefix** between all pairs of integers `(x, y)` such that `x` belongs to `arr1` and `y` belongs to `arr2`.

Return the length of the **longest** common prefix among all pairs. If no common prefix exists among them, return `0`.

**Example 1:**

```
Input: a = "11", b = "1"
Output: "100"
Input: arr1 = [1,10,100], arr2 = [1000]
Output: 3
Explanation: There are 3 pairs (arr1[i], arr2[j]):
- The longest common prefix of (1, 1000) is 1.
- The longest common prefix of (10, 1000) is 10.
- The longest common prefix of (100, 1000) is 100.
The longest common prefix is 100 with a length of 3.
```

## 题意
> ...

## 题解
**Example 2:**

### 思路1
> ...
Find the Length of the Longest Common Prefix
```go
```

Input: arr1 = [1,2,3], arr2 = [4,4,4]
Output: 0
Explanation: There exists no common prefix for any pair (arr1[i], arr2[j]), hence we return 0.
Note that common prefixes between elements of the same array do not count.
```

## 结语

Expand Down
Original file line number Diff line number Diff line change
@@ -1,5 +1,47 @@
package Solution

func Solution(x bool) bool {
return x
import (
"strconv"
)

type trieNode3043 struct {
child [10]*trieNode3043
}

func (r *trieNode3043) insert(intStr string) {
walker := r
for i := range intStr {
index := intStr[i] - '0'
if walker.child[index] == nil {
walker.child[index] = &trieNode3043{child: [10]*trieNode3043{}}
}
walker = walker.child[index]
}
}

func (r *trieNode3043) prefixMatch(intStr string) int {
walker := r
i := 0
for ; i < len(intStr); i++ {
index := intStr[i] - '0'
if walker.child[index] == nil {
break
}
walker = walker.child[index]
}
return i
}

func Solution(arr1 []int, arr2 []int) int {
ans := 0
tree := &trieNode3043{}
for _, intVal := range arr1 {
v := strconv.Itoa(intVal)
tree.insert(v)
}
for _, intVal := range arr2 {
v := strconv.Itoa(intVal)
ans = max(ans, tree.prefixMatch(v))
}
return ans
}
Original file line number Diff line number Diff line change
Expand Up @@ -10,30 +10,29 @@ func TestSolution(t *testing.T) {
// 测试用例
cases := []struct {
name string
inputs bool
expect bool
a1, a2 []int
expect int
}{
{"TestCase", true, true},
{"TestCase", true, true},
{"TestCase", false, false},
{"TestCase1", []int{1, 10, 100}, []int{1000}, 3},
{"TestCase2", []int{1, 2, 3}, []int{4, 4, 4}, 0},
}

// 开始测试
for i, c := range cases {
t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
got := Solution(c.inputs)
got := Solution(c.a1, c.a2)
if !reflect.DeepEqual(got, c.expect) {
t.Fatalf("expected: %v, but got: %v, with inputs: %v",
c.expect, got, c.inputs)
t.Fatalf("expected: %v, but got: %v, with inputs: %v %v",
c.expect, got, c.a1, c.a2)
}
})
}
}

// 压力测试
// 压力测试
func BenchmarkSolution(b *testing.B) {
}

// 使用案列
// 使用案列
func ExampleSolution() {
}
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