Time - Quin #34
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Time - Quin #34
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CheezItMan
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Oct 7, 2020
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| # Time Complexity: O(m + n + nlog(n)) | ||
| # Space Complexity: O(n) | ||
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| def grouped_anagrams(strings) |
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👍 I would say this is n * m log m where n is the number of strings and m is the length of the strings. Or if the strings are all less than a certain size, O(n) for time complexity.
Otherwise well done.
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| # Time Complexity: O(n log(n)) | ||
| # Space Complexity: O(n) | ||
| def top_k_frequent_elements(list, k) |
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👍 , is there a way to do this in O(nk) time?
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