Space - Stephanie #31
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CheezItMan
reviewed
Sep 8, 2020
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| # Time Complexity: O(1) bc it only adds one thing regardless of how big the list is | ||
| # Space Complexity: O(1) | ||
| def add_first(value) |
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| if @head.nil? | ||
| @head = Node.new(value) | ||
| else | ||
| @head = Node.new(value, @head) | ||
| end |
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Could be simplified as:
Suggested change
| if @head.nil? | |
| @head = Node.new(value) | |
| else | |
| @head = Node.new(value, @head) | |
| end | |
| @head = Node.new(value, @head) |
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| # Time Complexity: O(n) because worst case it needs to run through all items in list | ||
| # Space Complexity: O(1) | ||
| def search(value) |
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| # method to return the max value in the linked list | ||
| # returns the data value and not the node | ||
| def find_max |
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| # Time Complexity: O(n) bc it has to run through every item | ||
| # Space Complexity: O(1) | ||
| def find_min |
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| # Time Complexity: O(n) bc it has to go thru every item on the list | ||
| # Space Complexity: O(1) | ||
| def visit |
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| # Time Complexity: O(n) because you could look through entire list before you found specified value | ||
| # Space Complexity: O(1) | ||
| def delete(value) |
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| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def get_first |
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| # method that inserts a given value as a new last node in the linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def add_last(value) |
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| # method that returns the value of the last node in the linked list | ||
| # returns nil if the linked list is empty | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def get_last |
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