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Finished the assignment #49
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…ind_smallest, reverse and binary_search.
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Ana, well done. Take a look at my comment on find_smallest
and let me know what questions you have there. Thanks for getting this in.
@@ -0,0 +1,7 @@ | |||
<?xml version="1.0" encoding="UTF-8"?> |
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I suggest you add .idea
to your .gitignore
file.
i += 1 | ||
end | ||
return i | ||
end |
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end | |
end |
# Time complexity: Linear or O(n) --> it will iterate over each of the elements inside array. As the input grows, the greater the amount of time it takes to perform the function. | ||
# Space complexity: Constant of O(1) --> we only create one new variable and it doesnt depend on the size of the array. | ||
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||
def length(array) |
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👍
# Time complexity: Linear or O(n) --> it will iterate over each of the elements inside array. As the input grows, the greater the amount of time it takes to perform the function. | ||
# Space complexity: Constant of O(1) -> only one variable is created and its used throughout the entire function. | ||
def print_array(array) |
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# Time complexity: Linear or O(n) --> it will need to iterate over all elements in worse case, which means it will grow through each iteration. | ||
# Space complexity: Constant or O(1) | ||
def search(array, length, value_to_find) |
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# Time complexity: Linear or O(n) | ||
# Space complexity: Constant or O(1) | ||
def find_largest(array, length) |
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# Time complexity: Linear or O(n) | ||
# Space complexity: Constant or O(1) | ||
def reverse(array, length) |
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def find_smallest(array, length) | ||
raise NotImplementedError | ||
min = 0 |
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If the array has positive numbers starting min
at 0, will cause these to fail.
min = 0 | |
min = array[0] |
# Time complexity: Logarithmic or O(log n) - I remembered from lessons that binary search is 0(log n) | ||
# Space complexity: Constant or O(1)? | ||
def binary_search(array, length, value_to_find) |
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