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Aurora Anderson whiteboard 2 #4

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list.length.times do
result << list[rev]
rev -= 1
end

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This works and is easy to follow, but if requires iterating through the list twice. Can you think of a way to do this only iterating through the list once? (check the solutions branch for my solution)

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Revision looks good!


def switchPairs(list)

result = []

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This solution was supposed to modify the array in place, not create a new copy of the array.

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rewrote per your suggestions!

second = list[i+1]
result << second
result << first
list[i], list[i+1] = list[i+1], list[i]

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Ahh, fun! This is maybe kinda ruby magic (in the sense you can't do this in other languages), but I like it. :)

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2 participants