[박종훈] 5주차 답안 제출 #102
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[박종훈] 5주차 답안 제출 #102
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| @@ -0,0 +1,52 @@ | |||
| - 문제 : https://leetcode.com/problems/3sum/ | |||
| - time complexity : O(n^2) | |||
| - space complexity : O(1) (결과값을 고려하지 않은 알고리즘 자체의 공간 복잡도) | |||
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저는 이부분이 궁금했는데 결과값을 고려하지 않는다는 걸 따로 명시하지 않아도 결과값을 고려하지 않는게 당연한 걸까요?
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조합이 어떻게 나오냐에 따라서 공간복잡도가 달라질 것 같아서 저도 뭐라고 적을까 고민하다가
달레님 블로그를 보니깐 위와같이 표현하신것 같아서 참고해보았습니다 : )
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출력 결과 때문에 반드시 필요한 메모리 사용량은 공간 복잡도 분석을 할 때는 무시하는 것이 일반적입니다.
leokim0922
reviewed
May 30, 2024
|
커밋이 사라지면 자동으로 closed로 바뀌군요 ㄷㄷ... |
DaleSeo
approved these changes
May 31, 2024
| - space complexity : O(n) | ||
| - 블로그 링크 : https://algorithm.jonghoonpark.com/2024/05/08/leetcode-238 | ||
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| ## case 나눠서 풀기 |
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앗...! ㅋㅋ 주관적인 기준이였군요 ㅎㅎ
아래 풀이를 들었을 때 워낙 혁신이였어서 저는 재밌게 느꼈었네요...! ㅎㅎ
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| return Arrays.copyOfRange(counter.entrySet().stream() | ||
| .sorted(Map.Entry.<Integer, Integer>comparingByValue().reversed()) | ||
| .mapToInt(Map.Entry::getKey) | ||
| .toArray(), 0, k); |
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5주차 답안 제출합니다.
Top K Frequent Elements
Encode and Decode Strings
Product of Array Except Self
Longest Consecutive Sequence
3Sum