Skip to content

[wisdom08] Week1 #1132

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Closed
wants to merge 5 commits into from
Closed
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
7 changes: 7 additions & 0 deletions contains-duplicate/wisdom08.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,7 @@
class Solution(object):
def containsDuplicate(self, nums):
set_nums = set(nums)
if len(nums) == len(set_nums):
return False
else:
return True
10 changes: 10 additions & 0 deletions longest-consecutive-sequence/wisdom08.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,10 @@
def longestConsecutive(nums):
longest = 0

for num in nums:
length = 1
while num + length in nums:
length += 1
longest = max(longest, length)

return longest
10 changes: 10 additions & 0 deletions top-k-frequent-elements/wisdom08.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,10 @@
def topKFrequent(nums, k):
frequency = {}
for num in nums:
frequency[num] = frequency.get(num, 0) + 1

sorted_frequency = sorted(frequency, key=lambda num: frequency[num])
return sorted_frequency[-k:]


print(topKFrequent([1, 1, 1, 2, 2, 3], 2))
9 changes: 9 additions & 0 deletions two-sum/wisdom08.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,9 @@
class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:
dict = {}
for i, v in enumerate(nums):
diff = target - v
if diff in dict:
Copy link
Contributor

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

여기 if 구문이 dict를 순회하면서 맞는키가 있는지 보는건가로 알고 있었는데 키가 존재하는지만 확인하는 O(1) 메서드였네요..
코드 보면서 의아했는데 정말 깔끔하게 푸신거 보고 하나 배웠습니다!

return [i, dict[diff]]
else:
dict[v] = i