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HashSet 을 이용하여 중복된 숫자를 찾는 방식이네요. 저도 동일한 방식으로 풀었는데, kimbro97 님의 코드를 보니, return 이후에 굳이 else 를 쓰지 않으니 코드가 더 깔끔하네요. 👍