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[paran22] Week 01 solutions #1141

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Apr 6, 2025
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4 changes: 4 additions & 0 deletions contains-duplicate/paran22.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,4 @@
class Solution:
def containsDuplicate(self, nums: List[int]) -> bool:
unique_nums = set(nums)
return len(unique_nums) != len(nums)
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와우! 전 왜 이 방법을 생각 못했을까요?
set 으로 변환하면 중복된 값이 없어지고, length 가 줄어드니, 비교만하면 되는 것을...
Hashmap (Dictionary)를 이용해서 넣고 빼는 것과 비교해서 Time/Space Complexity 는 차이 없는데,
코드가 너무 깔끔하네요!
(근데, 코드 리뷰는 저를 넣으셔서 제가 일단 찾아 봤는데, 규칙상 paran22 님께서 제 코드 리뷰를 해주셔야 할 것 같아요. ㅎㅎ)

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넵! 확인했습니다 🙇

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제가 순서를 헷갈려서 리뷰어로 추가한 것 같아요 ㅜㅜ 리뷰 같이 진행해주셔서 감사합니다!!

10 changes: 10 additions & 0 deletions two-sum/paran22.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,10 @@
class Solution:
# 시간복잡도 : O(n)
def twoSum(self, nums: List[int], target: int) -> List[int]:
num_dict = {num: i for i, num in enumerate(nums)}

for i, first_num in enumerate(nums):
second_num = target - first_num
if second_num in num_dict and num_dict[second_num] != i:
return [i, num_dict[second_num]]