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[printjin-gmailcom] Week 14 Solutions #1628

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Jul 4, 2025
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13 changes: 13 additions & 0 deletions binary-tree-level-order-traversal/printjin-gmailcom.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,13 @@
class Solution:
def levelOrder(self, root):
result = []
def dfs(node, level):
if not node:
return
if len(result) == level:
result.append([])
result[level].append(node.val)
dfs(node.left, level + 1)
dfs(node.right, level + 1)
dfs(root, 0)
return result
6 changes: 6 additions & 0 deletions counting-bits/printjin-gmailcom.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,6 @@
class Solution:
def countBits(self, n):
ans = [0] * (n + 1)
for i in range(1, n + 1):
ans[i] = ans[i >> 1] + (i & 1)
return ans
10 changes: 10 additions & 0 deletions house-robber-ii/printjin-gmailcom.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,10 @@
class Solution:
def rob(self, nums):
if len(nums) == 1:
return nums[0]
def rob_linear(houses):
prev = curr = 0
for num in houses:
prev, curr = curr, max(curr, prev + num)
return curr
return max(rob_linear(nums[:-1]), rob_linear(nums[1:]))
14 changes: 14 additions & 0 deletions meeting-rooms-ii/printjin-gmailcom.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,14 @@
class Solution:
def minMeetingRooms(self, intervals):
if not intervals:
return 0
starts = sorted(i[0] for i in intervals)
ends = sorted(i[1] for i in intervals)
s = e = rooms = 0
while s < len(intervals):
if starts[s] < ends[e]:
rooms += 1
else:
e += 1
s += 1
return rooms
30 changes: 30 additions & 0 deletions word-search-ii/printjin-gmailcom.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,30 @@
class Solution:
def findWords(self, board: List[List[str]], words: List[str]) -> List[str]:
trie = {}
for word in words:
node = trie
for char in word:
node = node.setdefault(char, {})
node["$"] = word
rows, cols = len(board), len(board[0])
result = []
def dfs(r, c, node):
char = board[r][c]
if char not in node:
return
next_node = node[char]
word = next_node.pop("$", None)
if word:
result.append(word)
board[r][c] = "#"
for dr, dc in [(-1,0),(1,0),(0,-1),(0,1)]:
nr, nc = r + dr, c + dc
if 0 <= nr < rows and 0 <= nc < cols and board[nr][nc] != "#":
dfs(nr, nc, next_node)
board[r][c] = char
if not next_node:
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단어만 찾으면 된다고만 생각해서, Trie 구조를 정리(clean-up)하는 과정까지는 미처 생각하지 못했어요. 한참 찾아보면서 이 부분이 왜 중요한지 알게 되었고, 덕분에 새로운 개념을 배웠습니다. 👍

node.pop(char)
for r in range(rows):
for c in range(cols):
dfs(r, c, trie)
return result