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[do-heewan] WEEK 2 solutions #1748
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                valid anagram
              
              
                Do-heewan 13a5cdf
              
                climbing stairs
              
              
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              | Original file line number | Diff line number | Diff line change | 
|---|---|---|
| @@ -0,0 +1,11 @@ | ||
| class Solution: | ||
| def climbStairs(self, n: int) -> int: | ||
| dp = [0] * 46 | ||
| dp[1] = 1 | ||
| dp[2] = 2 | ||
|  | ||
| for i in range(3, n+1): | ||
| dp[i] = dp[i-1] + dp[i-2] | ||
|  | ||
| return dp[n] | ||
|  | 
  
    
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              | Original file line number | Diff line number | Diff line change | 
|---|---|---|
| @@ -0,0 +1,16 @@ | ||
| class Solution: | ||
| def productExceptSelf(self, nums: List[int]) -> List[int]: | ||
| result = [] | ||
|  | ||
| x = 1 | ||
| for element in nums: | ||
| result.append(x) | ||
| x *= element | ||
|  | ||
| x = 1 | ||
| for i in range(len(nums)-1, -1, -1): | ||
| result[i] *= x | ||
| x *= nums[i] | ||
|  | ||
| return result | ||
|  | ||
  
    
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              | Original file line number | Diff line number | Diff line change | 
|---|---|---|
| @@ -0,0 +1,4 @@ | ||
| class Solution: | ||
| def isAnagram(self, s: str, t: str) -> bool: | ||
| return sorted(s) == sorted(t) | ||
| There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 간단하고 직관적인 풀이로 하지만 Counter 이용에 대한 아이디어도 한 번은 생각해보시길 바랍니다 :) | ||
|  | ||
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저는 배열을 여러개 이용해서 풀어서 공간 복잡도가 높아지는 문제점이 있었는데, do-heewan님처럼 이렇게 하나의 배열로 간단하게 해결할 수 있다는 인사이트 얻고 가요. 이번주도 고생 많으셨습니다!