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[FEhyoeun] WEEK 02 solutions #2036
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,13 @@ | ||
| const cache: number[] = []; | ||
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| function climbStairs(n: number): number { | ||
| if(n === 1) return 1 | ||
| if(n === 2) return 2; | ||
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| // cache 값 있을 때 | ||
| if(cache[n]) return cache[n] | ||
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| // cache 값 없을 때 | ||
| cache[n] = climbStairs(n - 1) + climbStairs(n - 2); | ||
| return cache[n] | ||
| }; |
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,22 @@ | ||
| function isAnagram(s: string, t: string): boolean { | ||
| let sObj = {} | ||
| let tObj = {} | ||
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| s.split('').sort().map((sChar) => { | ||
| if(sChar in sObj) { | ||
| sObj[sChar] += 1 | ||
| } else { | ||
| sObj[sChar] = 1 | ||
| } | ||
| }) | ||
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| t.split('').sort().map((tChar) => { | ||
| if(tChar in tObj) { | ||
| tObj[tChar] += 1 | ||
| } else { | ||
| tObj[tChar] = 1 | ||
| } | ||
| }) | ||
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| return JSON.stringify(sObj) === JSON.stringify(tObj) | ||
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Contributor
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 반환할때 // 예시
for (let key in sObj) {
if (sObj[key] !== tObj[key]) return false
}그리고 객체 2개가 아닌 1개를 사용해서 해당 문제를 푸는 방법도 있을 것 같아요 : ) |
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| }; | ||
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sort()메소드를 사용하면 시간 복잡도가 O(n log n)가 된다고 알고 있습니다.작성해주신 전체 코드에서 마지막 반환값 순서를 보장하기 위해 sort처리를 하신 것 같은데 다른 방법으로 시간복잡도를 개선할 수 있을 것 같아요!